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X^2+8X-9=X
We move all terms to the left:
X^2+8X-9-(X)=0
We add all the numbers together, and all the variables
X^2+7X-9=0
a = 1; b = 7; c = -9;
Δ = b2-4ac
Δ = 72-4·1·(-9)
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{85}}{2*1}=\frac{-7-\sqrt{85}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{85}}{2*1}=\frac{-7+\sqrt{85}}{2} $
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